dtc: Don't abuse struct fdt_reserve_entry

struct fdt_reserve_entry is defined in fdt.h to exactly mirror the
in-memory layout of a reserve entry in the flattened tree.  Since that is
always big-endian, it uses fdt64_t elements, which have sparse annotations
marking them as not native endian.

However, in dtc, we also use struct fdt_reserve_entry inside struct
reserve_info, and use it with native endian values.  This will cause sparse
errors.

This stops this abuse, making struct reserve_info have its own native
endian fields for the same information.

Signed-off-by: David Gibson <david@gibson.dropbear.id.au>
This commit is contained in:
David Gibson
2017-03-06 12:04:45 +11:00
parent fa8bc7f928
commit 49300f2ade
5 changed files with 21 additions and 22 deletions

View File

@@ -319,8 +319,8 @@ struct reserve_info *build_reserve_entry(uint64_t address, uint64_t size)
memset(new, 0, sizeof(*new));
new->re.address = address;
new->re.size = size;
new->address = address;
new->size = size;
return new;
}
@@ -599,13 +599,13 @@ static int cmp_reserve_info(const void *ax, const void *bx)
a = *((const struct reserve_info * const *)ax);
b = *((const struct reserve_info * const *)bx);
if (a->re.address < b->re.address)
if (a->address < b->address)
return -1;
else if (a->re.address > b->re.address)
else if (a->address > b->address)
return 1;
else if (a->re.size < b->re.size)
else if (a->size < b->size)
return -1;
else if (a->re.size > b->re.size)
else if (a->size > b->size)
return 1;
else
return 0;