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BpfRingBuf.h - implement wait()

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Test: TreeHugger, atest BpfRingbufTest
Signed-off-by: Maciej Żenczykowski <maze@google.com>
Change-Id: I2696077caf4de27dd64e4af1c45a13844ed186c9
This commit is contained in:
Maciej Żenczykowski
2023-11-09 11:12:03 -08:00
parent 9748f3b2f0
commit ddb0ab8c61
2 changed files with 31 additions and 2 deletions
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16
staticlibs/native/bpf_headers/BpfRingbufTest.cpp
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@@ -74,11 +74,27 @@ class BpfRingbufTest : public ::testing::Test {
ASSERT_RESULT_OK(result);
EXPECT_TRUE(result.value()->isEmpty());
struct timespec t1, t2;
EXPECT_EQ(0, clock_gettime(CLOCK_MONOTONIC, &t1));
EXPECT_FALSE(result.value()->wait(1000 /*ms*/)); // false because wait should timeout
EXPECT_EQ(0, clock_gettime(CLOCK_MONOTONIC, &t2));
long long time1 = t1.tv_sec * 1000000000LL + t1.tv_nsec;
long long time2 = t2.tv_sec * 1000000000LL + t2.tv_nsec;
EXPECT_GE(time2 - time1, 1000000000 /*ns*/); // 1000 ms as ns
for (int i = 0; i < n; i++) {
RunProgram();
}
EXPECT_FALSE(result.value()->isEmpty());
EXPECT_EQ(0, clock_gettime(CLOCK_MONOTONIC, &t1));
EXPECT_TRUE(result.value()->wait());
EXPECT_EQ(0, clock_gettime(CLOCK_MONOTONIC, &t2));
time1 = t1.tv_sec * 1000000000LL + t1.tv_nsec;
time2 = t2.tv_sec * 1000000000LL + t2.tv_nsec;
EXPECT_LE(time2 - time1, 1000000 /*ns*/); // in x86 CF testing < 5000 ns
EXPECT_THAT(result.value()->ConsumeAll(callback), HasValue(n));
EXPECT_TRUE(result.value()->isEmpty());
EXPECT_EQ(output, TEST_RINGBUF_MAGIC_NUM);